백준 2908 상수

문제설명

#include <iostream>
using namespace std;

int reverse(int n)
{
	int a, b, c, val;
	a = n % 10;
	n /= 10;
	b = n % 10;
	n /= 10;
	c = n % 10;
	val = a * 100 + b * 10 + c;
	return val;
}
int main()
{
	int num, num2;
	int re_num, re_num2;

	cin >> num >> num2;

	re_num = reverse(num);
	re_num2 = reverse(num2);
	
	if (re_num > re_num2)cout << re_num;
	else cout << re_num2;
	return 0;
}